Kathis Posted December 3, 2024 Report Share Posted December 3, 2024 Day 2: So we're going to still a bit easy mode, but not so easy for some of you. In October we had a cypher event. The most common one was a Caesar cypher. It was very simple you just had to shift the alphabet a bit and convert the letters back. However we're going to do something a bit different. For all the odd letters I have shifted to the Left by 4. For all the even letters I have shifted to the right by 6. Good luck to everyone. Quote Link to comment Share on other sites More sharing options...
Kathis Posted December 4, 2024 Author Report Share Posted December 4, 2024 The day is done the code is expired. The solution was XBEDIFWPIHWEULXD Here is how you were to solve it. We have the code THAJELSVENSKQRTJ we then had the instructions of shifting all the odd letters, and the even letters. I have shifted to the Left by 4 which meant you had to shift them 4 to the right. It if helps think of a number line. Left on a number line is subtraction, right on a number line is addition. ABCDEFGHIJKLMNOPQRSTUVWXYZ A + 4 = E E + 4 = I Q + 4 = U S + 4 = W T + 4 = X THAJELSVENSKQRTJ so all those bolded letters get changed to the correct letters now. You were told that I have shifted to the right by 6, you do the same thing, only this time you move it to the left. H - 6 = B J - 6 = D K - 6 = E L - 6 = F N - 6 = H R - 6 = L V - 6 = P THAJELSVENSKQRTJ so all the bolded letters get changed to the correct letters. This would result in XBEDIFWPIHWEULXD Had the letter went below A, or above Z, you would just loop around and continue counting. Y + 4 = C | B - 6= V Now you know how to do a Caesar Cypher Quote Link to comment Share on other sites More sharing options...
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